UVa 624 - CD
传送门
题意
输出让磁带装最多的歌曲的分钟数
思路
0-1背包,增加了输出解。因为我是顺序推过去的,就是逆序输出来。
代码
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 15000;
int d[MAXN], CD[25], vis[25][MAXN];
int main()
{
//freopen("input.txt", "r", stdin);
int T, i, j, n, total;
while (~scanf("%d", &total))
{
scanf("%d", &n);
for (i = 1; i <= n; i++)
scanf("%d", &CD[i]);
memset(d, 0, sizeof(d));
memset(vis, 0, sizeof(vis));
for (i = 1; i <= n; i++)
{
for (j = total; j >= CD[i]; j--)
{
if (d[j] < d[j - CD[i]] + CD[i])
{
d[j] = d[j - CD[i]] + CD[i];
vis[i][j] = 1;
}
}
}
for (i = n, j = d[total]; i >= 1 && j > 0; i--)
{
if (vis[i][j])
{
printf("%d ", CD[i]);
j -= CD[i];
}
}
printf("sum:%d\n", d[total]);
}
return 0;
}