UVa 10635 - Prince and Princess
传送门
UVa 10635 - Prince and Princess
思路
学习了LCS的$O(nlogn)$解法。
代码
#include <bits/stdc++.h>
using namespace std;
const int INF = 0x3f3f3f3f;
int Hash[70000];
int main()
{
//freopen("input.txt", "r", stdin);
int T, i, j, an, bn, n, cases = 0;
scanf("%d", &T);
while (T--)
{
memset(Hash, 0, sizeof Hash);
vector<int> ve;
scanf("%d%d%d", &n, &an, &bn);
int temp = 1;
//ve.push_back(temp);
for (i = 1; i <= an + 1; i++)
{
scanf("%d", &temp);
Hash[temp] = i;
}
for (i = 0; i <= bn; i++)
{
scanf("%d", &temp);
if (temp == 0)
continue;
int v = Hash[temp];
if (ve.empty() || v > ve.back())
ve.push_back(v);
else
{
int t = lower_bound(ve.begin(), ve.end(), v) - ve.begin();
ve[t] = v;
}
}
printf("Case %d: %d\n", ++cases, ve.size());
}
return 0;
}