UVa 567 - Risk

传送门

UVa 567 - Risk

题意

求点到点的最短路

思路

Floyd模板题

代码

#include <bits/stdc++.h>
using namespace std;
#define LL long long
#pragma comment(linker, "/STACK:102400000,102400000")
const int MAXN = 20 + 1;
const int INF = 0x3f3f3f3f;
 
int dis[MAXN][MAXN];
 
void Floyd()
{
    for (int k = 1; k < MAXN; k++)
        for (int i = 1; i < MAXN; i++)
            for (int j = 1; j < MAXN; j++)
                dis[i][j] = min(dis[i][k] + dis[k][j], dis[i][j]);
}
 
int main()
{
    //freopen("input.txt", "r", stdin);
    int n, i, j, a, cases = 0, st, ed;
    while (~scanf("%d", &n))
    {
        //read data
        for (i = 1; i < MAXN; i++)
            for (j = 1; j < MAXN; j++)
                dis[i][j] = (i == j ? 0 : INF);
        for (i = 0; i < n; i++)
        {
            scanf("%d", &a);
            dis[1][a] = dis[a][1] = 1;
        }
        for (i = 2; i < 20; i++)
        {
            scanf("%d", &n);
            for (j = 0; j < n; j++)
            {
                scanf("%d", &a);
                dis[i][a] = dis[a][i] = 1;
            }
        }
        Floyd();
        scanf("%d", &n);
        printf("Test Set #%d\n", ++cases);
        for (i = 0; i < n; i++)
        {
            scanf("%d%d", &st, &ed);
            printf( "%2d to %2d: %d\n", st, ed, dis[st][ed]);
        }
        printf("\n");
    }
    return 0;
}

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