UVa 10048 - Audiophobia

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UVa 10048 - Audiophobia

题意

找出经过任意两点间的权的最大值

思路

改一下Floyd就行。

代码

#include <bits/stdc++.h>
using namespace std;
#define LL long long
#pragma comment(linker, "/STACK:102400000,102400000")
const int MAXN = 100 + 10;
const int INF = 0x3f3f3f3f;
 
int dis[MAXN][MAXN], mp[MAXN][MAXN], n;
 
void Floyd()
{
    for (int k = 1; k <= n; k++)
        for (int i = 1; i <= n; i++)
            for (int j = 1; j <= n; j++)
                dis[i][j] = min(max(dis[i][k], dis[k][j]), dis[i][j]);
}
 
int main()
{
    //freopen("input.txt", "r", stdin);
    int nc, nq, i, j, a, b, c, tt = 0, cases = 0;
    while (scanf("%d%d%d", &n, &nc, &nq), n + nc + nq)
    {
        if (tt++)
            printf("\n");
        for (i = 0; i <= n; i++)
            for (j = 0; j <= n; j++)
                dis[i][j] = (i == j ? 0 : INF);
        for (i = 0; i < nc; i++)
        {
            scanf("%d%d%d", &a, &b, &c);
            dis[a][b] = dis[b][a] = c;
        }
        Floyd();
        printf("Case #%d\n", ++cases);
        for (i = 0; i < nq; i++)
        {
            scanf("%d%d", &a, &b);
            if (dis[a][b] == INF)
                printf("no path\n");
            else
                printf("%d\n", dis[a][b]);
        }
    }
    return 0;
}

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