UVa 10048 - Audiophobia
传送门
题意
找出经过任意两点间的权的最大值
思路
改一下Floyd就行。
代码
#include <bits/stdc++.h>
using namespace std;
#define LL long long
#pragma comment(linker, "/STACK:102400000,102400000")
const int MAXN = 100 + 10;
const int INF = 0x3f3f3f3f;
int dis[MAXN][MAXN], mp[MAXN][MAXN], n;
void Floyd()
{
for (int k = 1; k <= n; k++)
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
dis[i][j] = min(max(dis[i][k], dis[k][j]), dis[i][j]);
}
int main()
{
//freopen("input.txt", "r", stdin);
int nc, nq, i, j, a, b, c, tt = 0, cases = 0;
while (scanf("%d%d%d", &n, &nc, &nq), n + nc + nq)
{
if (tt++)
printf("\n");
for (i = 0; i <= n; i++)
for (j = 0; j <= n; j++)
dis[i][j] = (i == j ? 0 : INF);
for (i = 0; i < nc; i++)
{
scanf("%d%d%d", &a, &b, &c);
dis[a][b] = dis[b][a] = c;
}
Floyd();
printf("Case #%d\n", ++cases);
for (i = 0; i < nq; i++)
{
scanf("%d%d", &a, &b);
if (dis[a][b] == INF)
printf("no path\n");
else
printf("%d\n", dis[a][b]);
}
}
return 0;
}