UVa 11995 - I Can Guess the Data Structure!
传送门
UVa 11995 - I Can Guess the Data Structure!
题意
给两个操作,一进一出(XD),判断是属于哪种数据结构。
思路
模拟。有STL真是太方便了。。
代码
#include <bits/stdc++.h>
using namespace std;
#define LL long long
#define MP(a, b) make_pair(a, b)
const int MAXN = 1000 + 10;
const int INF = 0x3f3f3f3f;
queue<int> qu;
priority_queue<int> pqu;
stack<int> stk;
struct COM
{
int a, num;
}cmd[MAXN];
int vis[4];
void Init()
{
while (!qu.empty())
qu.pop();
while (!pqu.empty())
pqu.pop();
while (!stk.empty())
stk.pop();
}
int main()
{
//freopen("input.txt", "r", stdin);
int n, i, j;
while (~scanf("%d", &n))
{
int ans = 0;
memset(vis, 0, sizeof vis);
Init();
for (i = 0; i < n; i++)
scanf("%d%d", &cmd[i].a, &cmd[i].num);
for (i = 0; i < n; i++)
{
if (cmd[i].a == 1)
qu.push(cmd[i].num);
else if (cmd[i].a == 2)
if (qu.empty() || qu.front() != cmd[i].num)
break;
else
qu.pop();
}
if (i == n)
vis[1] = 1, ans++;
for (i = 0; i < n; i++)
{
if (cmd[i].a == 1)
stk.push(cmd[i].num);
else if (cmd[i].a == 2)
if (stk.empty() || stk.top() != cmd[i].num)
break;
else
stk.pop();
}
if (i == n)
vis[2] = 1, ans++;
for (i = 0; i < n; i++)
{
if (cmd[i].a == 1)
pqu.push(cmd[i].num);
else if (cmd[i].a == 2)
if (pqu.empty() || pqu.top() != cmd[i].num)
break;
else
pqu.pop();
}
if (i == n)
vis[3] = 1, ans++;
if (ans == 0)
printf("impossible\n");
else if (ans > 1)
printf("not sure\n");
else
{
if (vis[1])
printf("queue\n");
else if (vis[2])
printf("stack\n");
else
printf("priority queue\n");
}
}
return 0;
}