HDU 1698 - Just a Hook (线段树 + 区间修改)
思路
学习了NotOnlySuccess大大的线段树。
代码
#include <cstdio>
#include <stack>
#include <set>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <functional>
#include <cstring>
#include <algorithm>
#include <cctype>
#include <ctime>
#include <cstdlib>
#include <fstream>
#include <string>
#include <sstream>
#include <map>
#include <cmath>
#define LL long long
#define lowbit(x) ((x) & (-x))
#define MP(a, b) make_pair(a, b)
#define MS(arr, num) memset(arr, num, sizeof(arr))
#define PB push_back
#define F first
#define S second
#define ROP freopen("input.txt", "r", stdin);
#define MID(a, b) (a + ((b - a) >> 1))
#define BitCount(x) __builtin_popcount(x)
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
using namespace std;
const int MAXN = 1e5 + 5;
const int MOD = 20071027;
typedef pair<int, int> pii;
typedef vector<int>::iterator viti;
typedef vector<pii>::iterator vitii;
struct SEGTREE
{
int col, sum;
}segt[MAXN << 2];
void PushDown(int rt, int m)
{
if (segt[rt].col)
{
segt[rt << 1].col = segt[rt << 1|1].col = segt[rt].col;
segt[rt << 1].sum = (m - (m >> 1)) * segt[rt].col;
segt[rt << 1|1].sum = (m >> 1) * segt[rt].col;
segt[rt].col = 0;
}
}
void PushUp(int rt)
{
segt[rt].sum = segt[rt << 1].sum + segt[rt << 1|1].sum;
}
void Update(int rt, int l, int r, int L, int R, int val)
{
if (L <= l && r <= R)
{
segt[rt].col = val;
segt[rt].sum = val * (r - l + 1);
return;
}
PushDown(rt, r - l + 1);
int mid = MID(l, r);
if (L <= mid) Update(rt << 1, l, mid, L, R, val);
if (R > mid) Update(rt << 1|1, mid + 1, r, L, R, val);
PushUp(rt);
}
void Build(int rt, int l, int r)
{
segt[rt].col = 0, segt[rt].sum = 1;
if (l == r) return;
int mid = MID(l, r);
Build(rt << 1, l, mid);
Build(rt << 1|1, mid + 1, r);
PushUp(rt);
}
int main()
{
//ROP;
int T, i, j, n, m, cases = 0;
scanf("%d", &T);
while (T--)
{
scanf("%d", &n);
Build(1, 1, n);
scanf("%d", &m);
int a, b, c;
while (m--)
{
scanf("%d%d%d", &a, &b, &c);
Update(1, 1, n, a, b, c);
}
printf("Case %d: The total value of the hook is %d.\n", ++cases, segt[1].sum);
}
return 0;
}