PKU 2239 - Selecting Courses (最大匹配 & Hungarian)
题意
有N个选修课,时间为周一到周日,1~12节课,现在要求选最多的课程。
左边是课程,右边是时间。时间可以表示成(nwek - 1) * 12。
最大匹配!
代码
#include <cstdio>
#include <stack>
#include <set>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <functional>
#include <cstring>
#include <algorithm>
#include <cctype>
#include <string>
#include <map>
#include <cmath>
#define LL long long
#define SZ(x) (int)x.size()
#define Lowbit(x) ((x) & (-x))
#define MP(a, b) make_pair(a, b)
#define MS(arr, num) memset(arr, num, sizeof(arr))
#define PB push_back
#define F first
#define S second
#define ROP freopen("input.txt", "r", stdin);
#define MID(a, b) (a + ((b - a) >> 1))
#define LC rt << 1, l, mid
#define RC rt << 1|1, mid + 1, r
#define LRT rt << 1
#define RRT rt << 1|1
#define BitCount(x) __builtin_popcount(x)
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
using namespace std;
const int MAXN = 300 + 10;
const int MOD = 1e9 + 7;
const int dir[][2] = { {-1, 0}, {1, 0}, {0, -1}, {0, 1} };
typedef pair<int, int> pii;
typedef vector<int>::iterator viti;
typedef vector<pii>::iterator vitii;
struct EDGE
{
int from, to;
};
int vis[MAXN], head[MAXN], next[MAXN * MAXN], link[MAXN];
int ncourse;
vector<EDGE> edges;
bool DFS(int u)
{
for (int i = head[u]; i != -1; i = next[i])
{
int &v = edges[i].to;
if (!vis[v])
{
vis[v] = 1;
if (link[v] == -1 || DFS(link[v]))
{
link[v] = edges[i].from;
return true;
}
}
}
return false;
}
int Hungary()
{
int res = 0;
MS(link, -1);
for (int u = 1; u <= ncourse; u++)
{
MS(vis, 0);
if (DFS(u)) res++;
}
return res;
}
void AddEdge(int from, int to)
{
edges.PB((EDGE){from, to});
int m = SZ(edges);
next[m - 1] = head[from];
head[from] = m - 1;
}
int main()
{
//ROP;
int i, j;
while (~scanf("%d", &ncourse))
{
MS(head, -1);
edges.clear();
int n;
for (i = 1; i <= ncourse; i++)
{
scanf("%d", &n);
while (n--)
{
int ncls, nwek;
scanf("%d%d", &nwek, &ncls);
int num = (nwek - 1) * 12 + ncls;
AddEdge(i, num);
}
}
printf("%d\n", Hungary());
}
return 0;
}