PKU 3692 - Kindergarten (最大团)

题意

幼儿园里女孩全部认识,男孩全部认识,一些女孩和一些男孩认识,要使他们都能认识才能组成一个圈子,求最大圈子人数。

思路

是求最大团,根据公式,就是V - 补图的最大匹配

代码

#include <cstdio>
#include <stack>
#include <set>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <functional>
#include <cstring>
#include <algorithm>
#include <cctype>
#include <string>
#include <map>
#include <cmath>
#define LL long long
#define SZ(x) (int)x.size()
#define Lowbit(x) ((x) & (-x))
#define MP(a, b) make_pair(a, b)
#define MS(arr, num) memset(arr, num, sizeof(arr))
#define PB push_back
#define F first
#define S second
#define ROP freopen("input.txt", "r", stdin);
#define MID(a, b) (a + ((b - a) >> 1))
#define LC rt << 1, l, mid
#define RC rt << 1|1, mid + 1, r
#define LRT rt << 1
#define RRT rt << 1|1
#define BitCount(x) __builtin_popcount(x)
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
using namespace std;
const int MAXN = 200 + 10;
const int MOD = 1e9 + 7;
const int dir[][2] = { {-1, 0}, {1, 0}, {0, -1}, {0, 1} };
 
typedef pair<int, int> pii;
typedef vector<int>::iterator viti;
typedef vector<pii>::iterator vitii;
 
int mp[MAXN][MAXN], nb;
 
struct EDGE
{
    int from, to;
};
 
struct BIMATCHING
{
    int link[MAXN], head[MAXN], next[MAXN * MAXN];
    bool vis[MAXN];
    vector<EDGE> edges;
 
    void init()
    {
        MS(link, -1); MS(head, -1);
        edges.clear();
    }
    void add_edge(int from, int to)
    {
        edges.PB((EDGE){from, to});
        int m = SZ(edges);
        next[m - 1] = head[from];
        head[from] = m - 1;
    }
 
    bool dfs(int u)
    {
        for (int v = 1; v <= nb; v++)
        {
            if (!vis[v] && mp[u][v])
            {
                vis[v] = 1;
                if (link[v] == -1 || dfs(link[v]))
                {
                    link[v] = u;
                    return true;
                }
            }
        }
        return false;
    }
 
    int solve(int n)  //n是待匹配的总数,这里默认从1开始
    {
        int res = 0;
        for (int i = 1; i <= n; i++)
        {
            MS(vis, 0);
            if (dfs(i)) res++;
        }
        return res;
    }
}hun;
 
int main()
{
    //ROP;
    int ng, n, i, j, cases = 0;
    while (scanf("%d%d%d", &ng, &nb, &n), ng + nb + n)
    {
        MS(mp, -1);
        hun.init();
        while (n--)
        {
            int a, b;
            scanf("%d%d", &a, &b);
            mp[a][b] = 0;
        }
        printf("Case %d: %d\n", ++cases, ng + nb - hun.solve(ng));
    }
    return 0;
}

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