UVa 1445 - Cubist Artwork
题意
给出正视图和侧视图(右),求最少有几个方块。
思路
贪心,如果正视图的个数和侧视图相同,就可以把它们看成是同一个东西。
$ans += i * max(f[i], r[i])$
代码
#include <cstdio>
#include <stack>
#include <set>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <functional>
#include <cstring>
#include <algorithm>
#include <cctype>
#include <string>
#include <map>
#include <iomanip>
#include <cmath>
#define LL long long
#define ULL unsigned long long
#define SZ(x) (int)x.size()
#define Lowbit(x) ((x) & (-x))
#define MP(a, b) make_pair(a, b)
#define MS(arr, num) memset(arr, num, sizeof(arr))
#define PB push_back
#define F first
#define S second
#define ROP freopen("input.txt", "r", stdin);
#define MID(a, b) (a + ((b - a) >> 1))
#define LC rt << 1, l, mid
#define RC rt << 1|1, mid + 1, r
#define LRT rt << 1
#define RRT rt << 1|1
#define BitCount(x) __builtin_popcount(x)
#define BitCountll(x) __builtin_popcountll(x)
#define LeftPos(x) 32 - __builtin_clz(x) - 1
#define LeftPosll(x) 64 - __builtin_clzll(x) - 1
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
using namespace std;
const double eps = 1e-6;
const int MAXN = 1e5 + 10;
const int MOD = 1000007;
typedef pair<int, int> pii;
typedef vector<int>::iterator viti;
typedef vector<pii>::iterator vitii;
int f[50], r[50];
int main()
{
//ROP;
int a, b, i, j;
while (scanf("%d%d", &a, &b), a + b)
{
MS(f, 0); MS(r, 0);
for (int i = 0; i < a; i++)
{
int tmp;
scanf("%d", &tmp);
f[tmp]++;
}
for (int i = 0; i < b; i++)
{
int tmp;
scanf("%d", &tmp);
r[tmp]++;
}
int ans = 0;
for (int i = 1; i <= 20; i++)
ans = ans + i * max(f[i], r[i]);
printf("%d\n", ans);
}
return 0;
}