UVa 11012 - Cosmic Cabbages (机智地枚举)
题意
找出两个点的最大的Manhattan Distance
思路
仰慕帆神。
| 求两个点的距离 | x1 - x2 | + | y1 - y2 | + | z1 - z2 | ，可以通过去绝对值，得到八个式子，其中的最大值就是答案。 |
不用担心不存在的形式计算出来的答案会影响结果，因为最后的答案一定会比这种答案大。
代码
#include <cstdio>
#include <stack>
#include <list>
#include <set>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <functional>
#include <cstring>
#include <iomanip>
#include <algorithm>
#include <cctype>
#include <string>
#include <map>
#include <cmath>
using namespace std;
#define LL long long
#define ULL unsigned long long
#define SZ(x) (int)x.size()
#define Lowbit(x) ((x) & (-x))
#define MP(a, b) make_pair(a, b)
#define MS(arr, num) memset(arr, num, sizeof(arr))
#define PB push_back
#define F first
#define S second
#define ROP freopen("input.txt", "r", stdin);
#define MID(a, b) (a + ((b - a) >> 1))
#define LC rt << 1, l, mid
#define RC rt << 1|1, mid + 1, r
#define LRT rt << 1
#define RRT rt << 1|1
#define BitCount(x) __builtin_popcount(x)
#define BitCountll(x) __builtin_popcountll(x)
#define LeftPos(x) 32 - __builtin_clz(x) - 1
#define LeftPosll(x) 64 - __builtin_clzll(x) - 1
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
const double eps = 1e-8;
const int MAXN = 100000 + 10;
const int MOD = 1000007;
const int dir[][2] = { {-1, 0}, {1, 0}, {0, -1}, {0, 1} };
typedef pair<int, int> pii;
typedef vector<int>::iterator viti;
typedef vector<pii>::iterator vitii;
struct ARRARY
{
int arr[3];
}num[MAXN];
int main()
{
//ROP;
int T, i, j, n, cases = 0;
scanf("%d", &T);
while (T--)
{
scanf("%d", &n);
for (i = 0; i < n; i++)
for (j = 0; j < 3; j++) scanf("%d", #[i].arr[j]);
int ans = -INF;
for (i = 0; i < (1<<3); i++)
{
int maxValue = -INF, minValue = INF;
for (j = 0; j < n; j++)
{
int sum = 0;
for (int k = 0; k < 3; k++)
{
if ((1<<k) & i) sum += num[j].arr[k];
else sum -= num[j].arr[k];
}
maxValue = max(maxValue, sum); minValue = min(minValue, sum);
}
ans = max(ans, maxValue - minValue);
}
printf("Case #%d: %d\n", ++cases, ans);
}
return 0;
}