HDU 1973 - Prime Path (BFS)
题意
给定一个初始素数和终止素数,问能不能通过改变一个数位最后到达终点。
思路
BFS
代码
#include <stack>
#include <cstdio>
#include <list>
#include <set>
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <functional>
#include <cstring>
#include <algorithm>
#include <cctype>
#include <string>
#include <map>
#include <cmath>
using namespace std;
#define LL long long
#define ULL unsigned long long
#define SZ(x) (int)x.size()
#define Lowbit(x) ((x) & (-x))
#define MP(a, b) make_pair(a, b)
#define MS(arr, num) memset(arr, num, sizeof(arr))
#define PB push_back
#define X first
#define Y second
#define ROP freopen("input.txt", "r", stdin);
#define MID(a, b) (a + ((b - a) >> 1))
#define LC rt << 1, l, mid
#define RC rt << 1|1, mid + 1, r
#define LRT rt << 1
#define RRT rt << 1|1
const double PI = acos(-1.0);
const int INF = 0x3f3f3f3f;
const double eps = 1e-8;
const int MAXN = 10000 + 10;
const int MOD = 29;
const int dir[][2] = { {-1, 0}, {0, -1}, { 1, 0 }, { 0, 1 } };
int cases = 0;
typedef pair<int, int> pii;
set<int> prime;
int vis[MAXN], ed, arr[5], mp[MAXN];
queue<pii> Q;
void GetPrimeTable()
{
int n = sqrt(MAXN + 0.5);
for (int i = 2; i < MAXN; i++) if (!vis[i])
{
prime.insert(i);
for (int j = i*i; j < MAXN; j += i) vis[j] = 1;
}
}
bool Solve(int style, int k, pii &ori)
{
int tmpNum = 0;
for (int i = 1; i <= 4; i++) tmpNum = ((style^i) ? tmpNum*10 + arr[i] : tmpNum*10 + k);
if (tmpNum <= 1000) return false;
if (!mp[tmpNum] && prime.count(tmpNum))
{
Q.push(MP(tmpNum, ori.Y + 1));
mp[tmpNum] = 1;
}
if (tmpNum == ed)
{
printf("%d\n", ori.Y + 1);
return true;
}
return false;
}
void Handle(int num)
{
for (int i = 4; i >= 1; i--)
{
arr[i] = num % 10;
num /= 10;
}
}
void BFS()
{
while (!Q.empty())
{
pii tmp = Q.front(); Q.pop();
Handle(tmp.X);
for (int i = 1; i <= 4; i++)
for (int j = 0; j < 10; j++) if (Solve(i, j, tmp)) return;
}
puts("Impossible");
}
int main()
{
//ROP;
GetPrimeTable();
int T;
scanf("%d", &T);
while (T--)
{
MS(mp, 0);
while (!Q.empty()) Q.pop();
int st;
scanf("%d%d", &st, &ed);
if (st == ed)
{
puts("0");
continue;
}
Q.push(MP(st, 0));
BFS();
}
}